3(x十2)的平方-(2x-1)(2x十1)得多少

2025-06-27 21:09:33
推荐回答(1个)
回答1:

如果是因式分解,那么:
3(x+2)²-(2x-1)(2x+1)
=3(x²+4x+4)-(4x²-1)
=3x²+12x+12-4x²+1
=-x²+12x+13
=-(x²-12x-13)
=-(x+1)(x-13)

如果是化简,那么:
3(x+2)²-(2x-1)(2x+1)
=3(x²+4x+4)-(4x²-1)
=3x²+12x+12-4x²+1
=-x²+12x+13