已知a눀+5ab=76,3b눀+2ab=51,求代数式a눀+11ab+9b눀的值

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2025-06-24 07:55:50
推荐回答(4个)
回答1:

a²+11ab+9b²
=a^2+5ab+6ab+9b^2
=(a^2+5ab)+3(3b^2+2ab)
=76+3*51
=229

回答2:

a²+11ab+9b²
=a²+5ab+6ab+9b²
=(a²+5ab)+3(3b²+2ab)
=76+153
=229

回答3:

a²+11ab+9b²
=a²+5ab+6ab+9b²
=76+3﹙3b²+2ab﹚
=76+3×51
=229

回答4:

a²+11ab+9b²
=a²+5ab+9b²+6ab
=76+3(3b²+2ab)
=76+3×51
=229