A=x/(x-1),B=3/(x^2-1)+1A=B所以x/(x-1)=3/(x^2-1)+1[x(x+1)-3]/(x^2-1)=1(x^2+x-3)/(x^2-1)=1x^2+x-3=x^2-1x=2经检验X=2是方程的解所以当x=2,A=B
