设+是任意常数,+,试求出一类微分方程+的一个形如+ ( +是常数)的积分因子,并进而求出其通解。翻译英文

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2025-06-24 07:03:16
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Suppose + is an arbitrary constant, try to derive the integral factor of a shape + of a class of differential equations ,such as + (+ is a constant), and its general solution.