已知4πR^2 —4πr^2=48π,2πR+2πr=12π 求R—r=??拜托各位大神

2025-06-27 17:17:30
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回答1:

4πR^2 —4πr^2=48π ==> R^2 -r^2 = 12 ==> (R+r)(R-r) = 12 2πR+2πr=12π ==> R + r = 6 ==> 6 * (R - r) = 12 ==> R - r = 2