x^2-5x+6=0→x1=2,x2=3 →集合A={2,3} →要使B包含于A,那么B的可能就有4种{2}或{3}或{2,3}或空集 →当B={2}时,将x=2代入,得a=-1 →此时,B={x|-x^2-x+6=0},解,得B={2,-3},不满足题意,舍去 →当B={3}时,a=-1/3 →此时,B={x|-x^2/3-x+6=0},解,得B={3,-6},不满足 →同理,B={2,3}时也无解 →当B为空集时,只需判别式小于0 →1-24a<0→a>1/24 →构成的集合:{a|a>1/24}