已知tan(a-π)=2,则sin눀a+sinacosa-2cos눀a=

2025-06-28 13:04:05
推荐回答(2个)
回答1:

tan(A-π)=2
tanA =2
=>
sinA = 2/√5 or - 2/√5
cosA =1/√5 or - 1/√5
(sinA)^2+sinA.cosA-2(cosA)^2
= 2/5 + 2/5 - 2(1/5)
=2/5

回答2:

上面的答案中(sinA)^2=4/5,答案错误