根号x^2-2x+1+根号x^2-6x+9括号1<=x<=3

根号x^2-2x+1+根号x^2-6x+9括号1&lt;=x&lt;=3
2025-06-27 15:31:27
推荐回答(2个)
回答1:

解答如下图片:

回答2:

根号x^2-2x+1+根号x^2-6x+9括号1<=x<=3
=√x²-2x+1+√x²-6x+9
=|x|-2x+1+|x|-6x+9
=2|x|-8x+10
因为1<=x<=3所以
=2x-8x+10
=10-6x
-8≤10-6x<4