大神帮我写个sql语句,愁人啊

2025-06-29 07:46:59
推荐回答(3个)
回答1:

delete article where body like '前面固定的字符串%后面固定的字符串'

回答2:

update article set body=substring(body,0,charindex('

123
',body))
+substring(body,charindex('
321
',body)+14,len(body))

回答3:

delete article where body like '

%
'