f(sinx⼀2)=1+cosx,求f(cosx)

2025-06-27 11:29:30
推荐回答(1个)
回答1:

f(sin(x/2))=1+2[cos(x/2)]^2-1=2[cos(x/2)]^2=2(1-[sin(x/2)]^2)
令sin(x/2)=t,则f(t)=2(1-t^2)
所以f(cosx)=2(1-[cosx]^2)=2(sinx)^2