令z=(e^(x-y))/y∂z/∂x=(e^(x-y))/ylnz=ln[(e^(x-y))/y]=ln(e^(x-y))-lny=x-y-lny等式两边对y求偏导数(1/z)×(∂z/∂y)=-1-1/y所以∂z/∂y=-[(y+1)e^(x-y)]/y²希望对你有帮助
对x的偏导数=e^(x-y)/y对y的偏导数=[-e^(x-y)y-e^(x-y)]/y^2
