(1)分别以DA,DC,DD1为x,y,z轴,
建立如图所示的空间直角坐标系D-xyz,
则A(2,0,0),C(0,4,0),D1(0,0,2),
E(0,
,2),F(1,4,0),4λ 1+λ
∴
=(2,0,?2),
D1A
=(0,4,?2),
D1C
当λ=
时,E(0,1,2),1 3
=(1,3,-2),EF
设平面D1AC的一个法向量为
=(x,y,z),n
则
,取y=1,则
?n
=2x?2z=0
D1A
?n
=4y?2z=0
D1C
=(2,1,2),n
cos<
,EF
>=n
=1
×3
14
,
14
42
∵cos<
,EF
>>0,∴<n
,EF
>是锐角,n
∴直线EF与平面D1AC所成角的正弦值为
.
14
42
(2)假设EF⊥EA,则
?EF