在液相中设苯的摩尔分数为x。则甲苯的摩尔分数为1-x。在常压下,100°沸腾,则饱和蒸汽压为101.3KPa180.1X + (1-X)74.18=101.3 解得X = 0.256 则甲苯的为0.744气相的苯摩尔分数为180.1*0.256/(180.1*0.256 + 74.18*0.744)=0.455 甲苯。。。。。。74.18*0.744/(180.1*0.256 + 74.18*0.744)=0.545追加点分呗