脱式计算: (1+3+5+7+…+299)-(2+4+6+…+298) 321-1-3-5-7-9-11-13-15-17-19 1+2+3+...+50

2025-06-27 17:37:13
推荐回答(1个)
回答1:

(1+3+5+7+…+299)-(2+4+6+…+298)
= 1 + (3-2) + (45-4) + ...... + (299-298)
= 1+(1+1+......+1 ) = 1+149 =150
321-1-3-5-7-9-11-13-15-17-19
= 312 - 10 * (1+19)/2
= 312 - 100 = 212
1+2+3+...+50
= 50 * (1+50) = 5050