已知a方分之1 2b方分之1=3,试用分式的基本性质求4ab-3a-6b分之2a-5b+4b的值

2025-06-29 07:16:04
推荐回答(1个)
回答1:

1/a+1/2b=3
2a-5ab+4b/4ab-3a-6b
分数式的分子分母上下同除以4ab商不变.(易知4ab不为0)
=(1/2b-5/4+1/a)/(1-3/4b-3/2a)
=(1/2b+1/a-5/4)/(1-3/2(1/a+1/2b)) 代入已知 1/a+1/2b=3
=(3-5/4)/(1-(3/2*3))
=(7/4)/1-9/2)
=7/4/(-7/2)
=-1/2