(1)设A=3x2-4x+5,B=2x-6x2+3,若多项式C+A-B=2x-4,求多项式C.(2)已知A=2x2+3xy-2x-1,B=-x2+xy-1

2025-06-25 06:36:06
推荐回答(1个)
回答1:

(1)C=2x-4+B-A
=2x-4+2x-6x2+3-(3x2-4x+5)
=2x-4+2x-6x2+3-3x2+4x-5
=-9x2+8x-6;

(2)3A+6B=3(2x2+3xy-2x-1)+6(-x2+xy-1)
=6x2+9xy-6x-3-6x2+6xy-6
=15xy-6x-6,
∵3A+6B的值与x无关,
∴15y-6=0,
解得:y=

2
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