(x+y+z)(-x-y+z)平方差公式

2025-06-27 21:26:14
推荐回答(4个)
回答1:

(x+y+z)(-x-y+z)
=z^2-(x+y)^2
=z^2-x^2-2xy-y^2

回答2:

(x+y+z)(-x-y+z)
=z^2-(x+y)^2
=z^2-x^2-2xy-y^2❤

回答3:

(x+y+z)(-x-y+z)
=(z+x+y)(z-x-y)
=[z+(x+y)][z-(x+y)]
=z^2-(x+y)^2

回答4:

(x+y+z)(-x-y+z)=(z+(x+y))(z-(x+y))= z^2-(x+y)^2= z^2 -(x^2 +2*x*y+y^2)