1.F= ( AC+A'BC+B'C ) ' + ABC' = ( (A+A'B+B')C ) ' + ABC' = ( (A+B+B’)C ) ' + ABC' = ( (A+1)C ) ' + ABC' = C' + ABC' =C’ 2.F= A(A'C + BD) + B(C+DE) + BC' =ABD+BC+BDE+BC’ =ABD+B+BDE =ABD+B =B 3.F=ABC+A'+B'+C' =ABC+(ABC)’ =1