设随机变量X~B(3,0.3),且Y=X^2,则P{Y=4}= 过程?

2025-06-28 06:55:24
推荐回答(1个)
回答1:

P{X=i}=(3Ci)(0.3^i)(1-0.3)^i (i=0,1,2,3)
概率分布如下
X | 0 1 2 3
P | 0.343 0.441 0.189 0.027
Y=X^2=4 即X=2 ,P{Y=4}= P{X=2}=0.189