作FC⊥l于C∴FC∥AD∥BE∴∠DAC=ACF，∠BCF=∠CBE∠ACF+∠BCF=∠ACB=90°又∵∠DAC+∠ACD=90°，∠BCE+∠CBE=90°∴∠DAC=∠BCE；∠ACD=∠CBE又∵AC=BC∴△ADC≌CEB亲，记得给好评哦
