曲面z=1-x2-y2在点(1 2,1 2,1 2)处的切平面方程是()

A.x+y+z-3/2=0B.x-y-z+3/2=0C.x-y+z-3/2=0D.x-y+z+3/2=0
2025-06-27 23:21:02
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回答1:

【答案】:A