用分部积分法求∫1÷√-x^2-x

2025-06-27 18:31:30
推荐回答(1个)
回答1:

说明:此题应该是“用分部积分法求∫[1/√(-x^2-x)]dx”.
∫[1/√(-x^2-x)]dx=∫[1/√(1-(x+1)^2)]d(x+1)
=arcsin(x+1)+C (C是积分常数).