初一数学因式分解:(x눀+5x+2)(x눀+5-1)-4

2025-06-27 15:31:16
推荐回答(1个)
回答1:

(1)原式=(x²+5x)²+(x²+5x)-8-4=(x²+5x)²+(x²+5x)-12=(x²+5x+4)(x²+5x-3)
=(x+4)(x+1)(x²+5x-3)
(2)原式=36(x+2y)³-4(x+2y)=4(x+2y)(9(x+2y)²-1)
=4(x+2y)(3(x+2y)+1)(3(x+2y)-1))
=4(x+2y)(3x+6y+1)(3x+6y-1)
(3)原式=(x-3y)²-(x-3y)-12=(x-3y-4)(x-3y+3)