在matlab中画三维曲面,定义域x 0到4pi y 0到4pi z=sin(x+sin(y))-x⼀10

2025-06-24 20:52:03
推荐回答(1个)
回答1:

x = linspace(0,4*pi,100);
y = linspace(0,4*pi,100);
[xx,yy] = meshgrid(x,y);
zz = sin(xx+sin(yy)) - xx./10;
mesh(xx,yy,zz)